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In [1]:
import proveit
from proveit import A, B, x
from proveit.logic.sets.inclusion import fold_subset_eq
theory = proveit.Theory() # the theorem's theory
In [2]:
%proving subset_eq_reflexive
With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
subset_eq_reflexive:
(see dependencies)
subset_eq_reflexive may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".
In [3]:
%qed
proveit.logic.sets.inclusion.subset_eq_reflexive has been proven.
Out[3]:
 step typerequirementsstatement
0generalization1  ⊢  
1instantiation2, 3  ⊢  
  : , : , :
2theorem  ⊢  
 proveit.logic.sets.inclusion.fold_subset_eq
3generalization4  ⊢  
4assumption  ⊢