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Expression of type NamedExprs

from the theory of proveit.logic.sets.inclusion

In [1]:
import proveit
# Automation is not needed when building an expression:
proveit.defaults.automation = False # This will speed things up.
proveit.defaults.inline_pngs = False # Makes files smaller.
%load_expr # Load the stored expression as 'stored_expr'
# import Expression classes needed to build the expression
from proveit import B, Lambda, NamedExprs, Variable, x
from proveit.logic import Boolean, Forall, InSet
In [2]:
# build up the expression from sub-expressions
sub_expr1 = Variable("_a", latex_format = r"{_{-}a}")
expr = NamedExprs(("lambda", Lambda(sub_expr1, sub_expr1)), ("${_{-}a}$", InSet(Forall(instance_param_or_params = [x], instance_expr = InSet(x, B)), Boolean)))
expr:
In [3]:
# check that the built expression is the same as the stored expression
assert expr == stored_expr
assert expr._style_id == stored_expr._style_id
print("Passed sanity check: expr matches stored_expr")
Passed sanity check: expr matches stored_expr
In [4]:
# Show the LaTeX representation of the expression for convenience if you need it.
print(stored_expr.latex())
\left\{ \begin{array}{l}
{\rm lambda}: \left[{_{-}a} \mapsto {_{-}a}\right]\\
{_{-}a}: \left(\left[\forall_{x}~\left(x \in B\right)\right] \in \mathbb{B}\right)\\
\end{array} \right\}

In [5]:
stored_expr.style_options()
no style options
In [6]:
# display the expression information
stored_expr.expr_info()
 core typesub-expressionsexpression
0NamedExprslambda: 1
${_{-}a}$: 2
1Lambdaparameter: 5
body: 5
2Operationoperator: 13
operands: 4
3ExprTuple5
4ExprTuple6, 7
5Variable
6Operationoperator: 8
operand: 10
7Literal
8Literal
9ExprTuple10
10Lambdaparameter: 15
body: 12
11ExprTuple15
12Operationoperator: 13
operands: 14
13Literal
14ExprTuple15, 16
15Variable
16Variable