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Expression of type Conditional

from the theory of proveit.logic.sets.functions.bijections

In [1]:
import proveit
# Automation is not needed when building an expression:
proveit.defaults.automation = False # This will speed things up.
proveit.defaults.inline_pngs = False # Makes files smaller.
%load_expr # Load the stored expression as 'stored_expr'
# import Expression classes needed to build the expression
from proveit import A, B, Conditional, Lambda, f, fx, x
from proveit.logic import Bijections, InSet
In [2]:
# build up the expression from sub-expressions
sub_expr1 = Bijections(A, B)
expr = Conditional(InSet(f, sub_expr1), InSet(Lambda(x, Conditional(fx, InSet(x, A))), sub_expr1))
expr:
In [3]:
# check that the built expression is the same as the stored expression
assert expr == stored_expr
assert expr._style_id == stored_expr._style_id
print("Passed sanity check: expr matches stored_expr")
Passed sanity check: expr matches stored_expr
In [4]:
# Show the LaTeX representation of the expression for convenience if you need it.
print(stored_expr.latex())
\left\{f \in \left[A \xrightarrow[\text{onto}]{\text{1-to-1}} B\right] \textrm{ if } \left[x \mapsto \left\{f\left(x\right) \textrm{ if } x \in A\right..\right] \in \left[A \xrightarrow[\text{onto}]{\text{1-to-1}} B\right]\right..
In [5]:
stored_expr.style_options()
namedescriptiondefaultcurrent valuerelated methods
condition_delimiter'comma' or 'and'commacomma('with_comma_delimiter', 'with_conjunction_delimiter')
In [6]:
# display the expression information
stored_expr.expr_info()
 core typesub-expressionsexpression
0Conditionalvalue: 1
condition: 2
1Operationoperator: 15
operands: 3
2Operationoperator: 15
operands: 4
3ExprTuple13, 6
4ExprTuple5, 6
5Lambdaparameter: 17
body: 7
6Operationoperator: 8
operands: 9
7Conditionalvalue: 10
condition: 11
8Literal
9ExprTuple18, 12
10Operationoperator: 13
operand: 17
11Operationoperator: 15
operands: 16
12Variable
13Variable
14ExprTuple17
15Literal
16ExprTuple17, 18
17Variable
18Variable