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In [1]:
import proveit
from proveit import defaults
from proveit import A, B
from proveit.logic.booleans.disjunction import false_or_true
theory = proveit.Theory() # the theorem's theory
In [2]:
%proving or_if_only_right
With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
or_if_only_right:
(see dependencies)
In [3]:
defaults.assumptions = or_if_only_right.all_conditions()
defaults.assumptions:
In [4]:
AeqF = A.evaluation()
AeqF:  ⊢  
In [5]:
BeqT = B.evaluation()
BeqT:  ⊢  
In [6]:
false_or_true
In [7]:
AorT = AeqF.sub_left_side_into(false_or_true, auto_simplify=False)
AorT:  ⊢  
In [8]:
ForT = BeqT.sub_left_side_into(AorT, auto_simplify=False)
ForT: ,  ⊢  
or_if_only_right may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".
In [9]:
%qed
proveit.logic.booleans.disjunction.or_if_only_right has been proven.
Out[9]:
 step typerequirementsstatement
0generalization1  ⊢  
1instantiation2, 3, 4,  ⊢  
  : , :
2theorem  ⊢  
 proveit.logic.equality.substitute_truth
3instantiation5, 6, 7  ⊢  
  : , :
4assumption  ⊢  
5theorem  ⊢  
 proveit.logic.equality.substitute_falsehood
6theorem  ⊢  
 proveit.logic.booleans.disjunction.false_or_true
7assumption  ⊢