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In [1]:
import proveit
from proveit import defaults
from proveit import A, B
from proveit.logic.booleans.disjunction import true_or_false
theory = proveit.Theory() # the theorem's theory
In [2]:
%proving or_if_only_left
With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
or_if_only_left:
(see dependencies)
In [3]:
defaults.assumptions = or_if_only_left.all_conditions()
defaults.assumptions:
In [4]:
AeqT = A.evaluation()
AeqT:  ⊢  
In [5]:
BeqF = B.evaluation()
BeqF:  ⊢  
In [6]:
true_or_false
In [7]:
AorF = AeqT.sub_left_side_into(true_or_false, auto_simplify=False)
AorF:  ⊢  
In [8]:
TorF = BeqF.sub_left_side_into(AorF, auto_simplify=False)
TorF: ,  ⊢  
or_if_only_left may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".
In [9]:
%qed
proveit.logic.booleans.disjunction.or_if_only_left has been proven.
Out[9]:
 step typerequirementsstatement
0generalization1  ⊢  
1instantiation2, 3, 4,  ⊢  
  : , :
2theorem  ⊢  
 proveit.logic.equality.substitute_falsehood
3instantiation5, 6, 7  ⊢  
  : , :
4assumption  ⊢  
5theorem  ⊢  
 proveit.logic.equality.substitute_truth
6theorem  ⊢  
 proveit.logic.booleans.disjunction.true_or_false
7assumption  ⊢