Proof of proveit.logic.booleans.disjunction.or_if_any theorem

import proveit
theory = proveit.Theory() # the theorem's theory

%proving or_if_any

With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
or_if_any:
(see dependencies)

or_if_any may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".