Proof of proveit.logic.booleans.disjunction.any_if_all theorem

import proveit
theory = proveit.Theory() # the theorem's theory

%proving any_if_all

With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
any_if_all:
(see dependencies)

any_if_all may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".