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Expression of type ExprTuple

from the theory of proveit.core_expr_types.tuples

In [1]:
import proveit
# Automation is not needed when building an expression:
proveit.defaults.automation = False # This will speed things up.
proveit.defaults.inline_pngs = False # Makes files smaller.
%load_expr # Load the stored expression as 'stored_expr'
# import Expression classes needed to build the expression
from proveit import ExprRange, ExprTuple, Function, Variable, f, i, j, m, n
In [2]:
# build up the expression from sub-expressions
sub_expr1 = Variable("_b", latex_format = r"{_{-}b}")
sub_expr2 = Variable("_a", latex_format = r"{_{-}a}")
expr = ExprTuple(ExprRange(sub_expr1, ExprRange(sub_expr2, Function(f, [sub_expr1, sub_expr2]), i, j), m, n))
expr:
In [3]:
# check that the built expression is the same as the stored expression
assert expr == stored_expr
assert expr._style_id == stored_expr._style_id
print("Passed sanity check: expr matches stored_expr")
Passed sanity check: expr matches stored_expr
In [4]:
# Show the LaTeX representation of the expression for convenience if you need it.
print(stored_expr.latex())
\left(f\left(m, i\right), f\left(m, i + 1\right), \ldots, f\left(m, j\right), f\left(m + 1, i\right), f\left(m + 1, i + 1\right), \ldots, f\left(m + 1, j\right), \ldots\ldots, f\left(n, i\right), f\left(n, i + 1\right), \ldots, f\left(n, j\right)\right)
In [5]:
stored_expr.style_options()
no style options
In [6]:
# display the expression information
stored_expr.expr_info()
 core typesub-expressionsexpression
0ExprTuple1
1ExprRangelambda_map: 2
start_index: 3
end_index: 4
2Lambdaparameter: 14
body: 6
3Variable
4Variable
5ExprTuple14
6ExprRangelambda_map: 7
start_index: 8
end_index: 9
7Lambdaparameter: 15
body: 11
8Variable
9Variable
10ExprTuple15
11Operationoperator: 12
operands: 13
12Variable
13ExprTuple14, 15
14Variable
15Variable