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Expression of type ExprArray

from the theory of proveit.core_expr_types.expr_arrays

In [1]:
import proveit
# Automation is not needed when building an expression:
proveit.defaults.automation = False # This will speed things up.
proveit.defaults.inline_pngs = False # Makes files smaller.
%load_expr # Load the stored expression as 'stored_expr'
# import Expression classes needed to build the expression
from proveit import A, B, ExprArray, ExprRange, IndexedVar, Variable, k, m, n
from proveit.numbers import one
In [2]:
# build up the expression from sub-expressions
sub_expr1 = Variable("_b", latex_format = r"{_{-}b}")
sub_expr2 = Variable("_a", latex_format = r"{_{-}a}")
sub_expr3 = [sub_expr1, sub_expr2]
expr = ExprArray(ExprRange(sub_expr1, [ExprRange(sub_expr2, IndexedVar(A, sub_expr3), one, n), ExprRange(sub_expr2, IndexedVar(B, sub_expr3), one, k)], one, m).with_explicit_parameterization())
expr:
In [3]:
# check that the built expression is the same as the stored expression
assert expr == stored_expr
assert expr._style_id == stored_expr._style_id
print("Passed sanity check: expr matches stored_expr")
Passed sanity check: expr matches stored_expr
In [4]:
# Show the LaTeX representation of the expression for convenience if you need it.
print(stored_expr.latex())
\begin{array}{cccccccc} 
 A_{1, 1} & A_{1, 2} & \cdots & A_{1, n} & B_{1, 1} & B_{1, 2} & \cdots & B_{1, k} \\
A_{2, 1} & A_{2, 2} & \cdots & A_{2, n} & B_{2, 1} & B_{2, 2} & \cdots & B_{2, k} \\
\begin{array}{c}:\\ A_{{_{-}b}, 1} \\:\end{array} & \begin{array}{c}:\\ A_{{_{-}b}, 2} \\:\end{array} & \ddots & \begin{array}{c}:\\ A_{{_{-}b}, n} \\:\end{array} & \begin{array}{c}:\\ B_{{_{-}b}, 1} \\:\end{array} & \begin{array}{c}:\\ B_{{_{-}b}, 2} \\:\end{array} & \ddots & \begin{array}{c}:\\ B_{{_{-}b}, k} \\:\end{array} \\
A_{m, 1} & A_{m, 2} & \cdots & A_{m, n} & B_{m, 1} & B_{m, 2} & \cdots & B_{m, k} \\
\end{array}

In [5]:
stored_expr.style_options()
namedescriptiondefaultcurrent valuerelated methods
justificationjustify to the 'left', 'center', or 'right' in the array cellscentercenterwith_justification
In [6]:
# display the expression information
stored_expr.expr_info()
 core typesub-expressionsexpression
0ExprTuple1
1ExprRangelambda_map: 2
start_index: 11
end_index: 3
2Lambdaparameter: 19
body: 5
3Variable
4ExprTuple19
5ExprTuple6, 7
6ExprRangelambda_map: 8
start_index: 11
end_index: 9
7ExprRangelambda_map: 10
start_index: 11
end_index: 12
8Lambdaparameter: 20
body: 13
9Variable
10Lambdaparameter: 20
body: 15
11Literal
12Variable
13IndexedVarvariable: 16
indices: 18
14ExprTuple20
15IndexedVarvariable: 17
indices: 18
16Variable
17Variable
18ExprTuple19, 20
19Variable
20Variable