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In [1]:
import proveit
from proveit import defaults
theory = proveit.Theory() # the theorem's theory
In [2]:
%proving set_not_equiv_contradiction
With these allowed/disallowed theorem/theory presumptions (e.g., to avoid circular dependencies), we begin our proof of
set_not_equiv_contradiction:
(see dependencies)
In [3]:
defaults.assumptions = set_not_equiv_contradiction.all_conditions()
defaults.assumptions:
In [4]:
A_not_equiv_B = defaults.assumptions[1]
A_not_equiv_B:
In [5]:
not_A_equiv_B = A_not_equiv_B.unfold()
not_A_equiv_B:  ⊢  
set_not_equiv_contradiction may now be readily provable (assuming required theorems are usable).  Simply execute "%qed".
In [6]:
not_A_equiv_B.derive_contradiction()
In [7]:
%qed
proveit.logic.sets.equivalence.set_not_equiv_contradiction has been proven.
Out[7]:
 step typerequirementsstatement
0generalization1  ⊢  
1instantiation2, 3, 4,  ⊢  
  :
2theorem  ⊢  
 proveit.logic.booleans.negation.negation_contradiction
3assumption  ⊢  
4instantiation5, 6  ⊢  
  : , :
5theorem  ⊢  
 proveit.logic.sets.equivalence.unfold_set_not_equiv
6assumption  ⊢